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t^2-13t-70=0
a = 1; b = -13; c = -70;
Δ = b2-4ac
Δ = -132-4·1·(-70)
Δ = 449
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{449}}{2*1}=\frac{13-\sqrt{449}}{2} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{449}}{2*1}=\frac{13+\sqrt{449}}{2} $
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